Solve the following system of simultaneous linear equations by the elimination method
2x+y =7
2x-3y =3
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Solve the following system of simultaneous linear equations by the elimination method
2x+y =7
2x-3y =3
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Verified answer
x = 3 , y = 1
(3,1) is the solution of the given equation
Answer:
2x+y=7 --------- equation 1
2x-3y=3 -------- equation 2
subtraction equation 1 and 2
2x+y=7
-2x+3y= -3
--------------
4y=4
therefore y = 4 / 4
therefore y = 1
substituting y=1 in equation 1
2x + 1 = 7
2x = 7-1
2x = 6
therefore x = 6 / 2
therefore x = 3
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Answer:
Given equations are
2x+y=7 ....(1)
and 2x−3y=3 ....(2)
Multiply equation (1) by 3,
6x+3y=21 ....(3)
Add equations (2) and (3) to eliminate y, we get
8x=24
⇒x=3
Substitute this value of x in equation (1),
2(3)+y=7
⇒6+y=7
⇒y=1
Therefore, solution is x=3,y=1.
Step-by-step explanation:
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