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Answer:
In right triangle ∆ABD by Pythagoras theorem,
(AB)² + (BD)² = (AD)²
= 5² + (BD)² = 9²
= (BD)² = = 81 45
= (BD)² = = 56
= BD = √56
= BD = 2√14
In right triangle ∆ABC by Pythagoras theorem,
(AB)² + (BC)² = (AC)²
= 5² + (BD - CD)² = (AC)²
= 25 + (BD /2 )= (AC)²
= 25 + (2√4/2) ² = (AC)²
= 25 + 14 = (AC)²
= 39= (AC)²
pls mark me as brainliest