solve the question given in the attachment
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solve the question given in the attachment
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Answer:
s.a. of all 20 cuboidal tins
area of tin required
S.A.of one tin=[l*b+b*h+l*h]
2[30*40+40*50+30*50]
2[120+2000+1500]
2*4700
9400
s.a. of 20 tins=20*9400
=88000cm^2
1m^2=1m*1m
=100cm*100cm
1m^2=10^4cm^2
=1cm^2=1/10^4m^2
s.a. of 20 tins=188000*1/10^4m^2
18.8m^2
cost of 1m^2 tin=rs.20
cost of 18.8m^2 tin=rs.20*18.8
ans.=Rs.376
please mark me as brainliest if this helped
Answer:
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Explanation:
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