solve this it is a challenge for brainly users who only wants to solve easy questions by copying from google and if possible answer my all pending questions in my profile
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solve this it is a challenge for brainly users who only wants to solve easy questions by copying from google and if possible answer my all pending questions in my profile
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Explanation:
The ball is released from top of tower.
The ball takes T seconds to reach the ground.
Position of ball (height of tower)
h = 1/2gT²
Position of ball at T/3 seconds
h' = 1/2g(T/3)²
h' = 1/2gT²/9
h' = 1/9 × 1/2gT²
h' = 1/9 × h
h' = h/9
h' is the distance covered by the ball in T/3 seconds.
Total height = h
Distance covered, h' = h/9
Therefore, Position of ball
= h - h'
= h - h/9
= 8h/9
Hope it helps!
Mark me brainliest!
Answer:
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Explanation:
We know that s=ut+12>2,orh=12gT2〈.U=0)
now for T/3 second , vertical distance moved is given by
h′=12g(T3)2⇒h′=12×gT29=h9
∴ Position of ball from ground =h-h9=8h9.