Solve this matrix problem.
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So,
det (A) = 0 (1)
But , determinant of matrix is :
det (A) = ( 4 x k ) - ( 3 x 2 )
Now , by (1) ,
( 4 x k ) - ( 3 x 2 ) = 0
4k - 6 = 0
4k = 6
k = 6/4
k = 3/2
Here is your answer...✌
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Inverse of matrix A doesn't exist
=> |A| = 0
(k×4) - (2×3) = 0
4k-6 = 0
4k = 6
k = 6/4
k = 3/2