solve this problem earlier I will givving him or her brainliest ansewr
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solve this problem earlier I will givving him or her brainliest ansewr
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Answer:
hi the answer will be
BCD=ACD
BCE = ABC
DCB= ADC
THANK YOU
Step-by-step explanation:
PLEASE MARK BRAINLIEST AS YOU HAVE SAID
AX is the bisector of angle BAC , P is any point on AX. Prove that the perpendiculars drawn from P to AB and AC are equal.
Construction: From X, draw LX⊥AC and XM⊥AB, And, join YC
Proof:
(I) In △AXL and △AXM
∠XAL=∠XAM (Given)
AX=AX (Common)
∠XLA=∠XMA (each 90
o
)
Thus, by ASA criterion of congruence
△AXL≅△AXM
And, by Corresponding Parts of Congruent Triangle (CPCT)
XL=XM
Therefore, X is equidistant from AC and AB
(ii) In △YTA and △YTC
AT=CT (Common)
∠YTA=∠YTC (Each 90
o
)
YT=YT
Thus, by SAS criterion of congruence
△YTA≅△YTC
And, by Corresponding Parts of Congruent Triangle (CPCT)
YA=YC
Therefore, Y is equidistant from A and C