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Question :
A ball is thrown vertically upward with acceleration -10 m/s². Stone was thrown with a speed of 25km/hr. Calculate maximum height it attains.
Answer :
Initial velocity = 25 km/hr
∴ 25 km/hr = 25 × 5/18 = 6.94 m/s
Acceleration = -10 m/s²
[Negative sign shows downward direction]
[tex]\star[/tex] Acceleration is said to be constant throughout the motion, we can easily apply equation of kinematics to solve this question.
Third equation of kinematics,
Velocity of ball at highest point = zero.
➝ 0² - (6.94)² = 2(-10)H
➝ 48.16 = 20H
➝ H = 2.4 m