solve this(similarity)
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using BPT ,
AD/DG=BE\GE......1
NOW,BC|| EF
USING BPT
BE/EG=CF/ FG......2
FROM 1&2
AD/DG=CF/FG.....3.
hence proved
2) in triangle DFG&ACG
FROM 3 ,
AD/DG=CF/GF
BY COMPONENDO,
AG/DG=CF/GF................4
AND Angle A is common
by using SAS test triangles are similar