Solve using Law of exponents:
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Answer:
Step-by-step explanation:
(1) 2^2/3* 2^1/3 [A^M*A^N=A^(M+N)]
= 2^(2/3+1/3)
= 2
(2) (3^1/5)^4
= 3^5/4 [(A^M)^N = A^MN]
(3)(7^1/5)/(7^1/3) [ A^M/A^N=A^M-N]
= 7^(1/5-1/3)
= 7^(-2/15)
(4) 13^(1/5) * 17^(1/5) [ A^M*B^M=( A*B)^M]
= (13*17)^(1/5)
= 221^(1/5)
(5)2 ^(2/3+1/5) [SAME AS 1]
= 2^(7/15)
(6) (1/3^3)^7
= (1/3)^21 [ SAME A S 2]
(7)11^(1/2)/11^(1/4)
= 11^(1/2-1/4)
=11^(1/4) [ SAME AS 3]
(8) 7^(1/2)*98^(1/2) [ SAME AS 4].
= (7*8)^(1/2)
= 56^(1/2).
HOPE THIS HELPS.