solve using substiution method y=6x+11 ; 2y-4x=14
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Given equation,
[tex]y = 6x+11\\2y-4x=14[/tex]
Subs, the 1st eq, in the 2nd eq. , we get,
[tex]2(6x+11)-4x=14\\12x+22-4x+14\\8x=14-22\\8x=-8\\\\\boxed{\boxed{\bold{x=-1}}}\\\boxed{\boxed{\bold{y=5}}}[/tex]
Answer:
2y-4x=14; y=6x+11
2(6x+11)-4x=14
12x+22-4x=14
8x+22=14
8x=14-22
8x=-8
x= -1
putting the value of x on y
y= -6+11
y=5
so the value is x=-1,y=5