Solve:A) Find the mean of all prime numbers up to 10.
(B) Find the mean proportional between 3 and 27.
(C) Divide 81 in to three parts in the ratio 2 : 3 : 4
(D) Given below figure shows a pair of parallel lines cut by a transversal. Find the
value of a and b, giving reason.
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Answer:
1.) The all prime numbers upto 30 are 2,3,5,7,11,13,17,19,23,29
sum of these observations=129
Number of their observation=10
Required mean=129÷10=12.9
2.)The mean proportional of 27 and 3 is √27×3=√81=9.
3.)Given ratio=2:3:4
Sum of their ratio=9
1st part=2/9×81=18
2nd part=3/9×81=27
3rd part= 4/9×81=36
4.)Each figure given below shows a pair of parallel lines cut by a transversal For each case, find a and b, giving reasons.
Answer:
A) prime numbers till 30 are as follows
2,3,5,7,11,13,17,19,23 and 29
Hence, the mean can be calculated as below
Mean = Sum of numbers / Number of numbers
(2+3+5+7+11+13+17+19+23+29)/10
We get,
=129/10
=12.9
Therefore, mean=12.9 Answer
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