Somebody please answer this question. Whoever answers first, I will mark as brainliest.
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Somebody please answer this question. Whoever answers first, I will mark as brainliest.
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Height of the tower is in terms of initial velocity as
Initial velocity = u
Acceleration, a = g
Final velocity, v = 3u
The stone thrown moves with initial velocity and acceleration as given, the height of the tower is calculated using equation of motion, we have,
Hey mate
Here
initial velocity=u
final velocity{v}=3u
acceleration=g{gravitational force 9.8 m/s ^2
so height of tower=distance covered by the obj
apply 3rd equation of motion
2as=v^2-u^2
=s=v^2-u^2/2
solved in picture
so , 2nd opt is correct
HOPE THIS HELPS
MARK IT BRAINLIEST
THANK U