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OD 16 cm
Also, sin 60°
- 26a)-
323 cm.
Area of the circle of radius 32 cm
2/3)
4 BC 32V3
22
-7683
1024
Let o be the centre of a circular table and ABC be the equilateral triangle
Then we draw ODL BC.
In ABD, we have: cos 60
OD
OB
OD
32
OBRadius 32 cm
BD
. BC 2BD
Area of the design (shaded region)
Area of equilateral AABC
X (32)
x32x 32-
x32x 32 x 3 c
22528
22 3
OB
BD
32
BD 163 cm