someone please help me out with this problem !!
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someone please help me out with this problem !!
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Step-by-step explanation:
Let the fixed charge be x rupees
And the additional charge be y
Now
27 = 3x+4y .....(eq1)
y = (27-3x) / 4
21 = 3x+2y .....(eq2)
y = (21-3x) /2
Now comparing the values of y
27-3x /4 = 21-3x / 2
(27-3x)2 = (21-3x)4
54 -6x = 84 -12x
6x = 84-54
x = 30/6
x = 5
Now
putting x = 5 in eq1
27 = 3×5 + 4y
27-15 = 4y
y = 12/4
y = 3
So the fixed charge for first three days is 5 rupees
And the additional charge is 3 rupees.
Step-by-step explanation: