Sonu is 4 year older than Monu. 8 year ago Sonu was three times Monu age find the age of Sonu and Monu
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Sonu is 4 year older than Monu. 8 year ago Sonu was three times Monu age find the age of Sonu and Monu
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Answer:
Let monu's age be X years
Age of Sonu = X + 4 yrs
Age of Sonu 8 yrs ago = X - 4 yrs
Age of Monu 8 yrs ago = X - 8 yrs
B.T.P,
(X-8)3 = X-4
or, 3X - 24 = X - 4
or, 3X - X = -4+24
or, 2X = 20
X = 10
Present age of Monu = 10yrs
Present age of Sonu = 10+4 = 14 yrs
Let us consider Present monu age = x yrs
Then five years ago monu age was = (x -5) yrs
Given five years ago sonu age was = 3(x -5) yrs = (3x -15) yrs
From above present age of sonu =3x -15+5 = 3x -10 yrs ----> equation 1
Ten years later monu age = (x + 10) yrs
Given 10 years later sonu age = 2(x + 10)yrs = 2x+20 yrs
From above present sonu age = 2x +20 -10 =2x +10 yrs ----> equation 2
As equation 1 and 2 both are for present age of sonu on equating both the equations
3x -10 = 2x +10 => 3x -2x = 10 + 10 => x = 20
Present age of monu = 20 yrs
Present sonu age can be calculated either by equation one are two
By equation 1:
Present age of sonu = 2x + 10 = 2×20 + 10 = 50 yrs