speech on urbanization for ASL class 9
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speech on urbanization for ASL class 9
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Answer:
Given,
P = Rs 1250
T = 3 years
R = 5% p.a.
$$\begin{lgathered}\mathsf{A = P \times (1 + \frac{R}{100} ) {}^{T}} \\\end{lgathered}$$
$$\begin{lgathered}\: \: \: \: \mathsf{= Rs \: \: 1250 \times (1 + \frac{5}{100} ) {}^{3}} \\\end{lgathered}$$
$$\begin{lgathered}\: \: \: \: \sf{= Rs \: \: 1250 \times \frac{105}{100} \times \frac{105}{100} \times \frac{105}{100}} \\\end{lgathered}$$
$$\: \: \: \: \sf{= Rs \: \: 1663.75}$$
CI = A - P
= Rs (1663.75 - 1250)
= Rs 413.75