subtract: 3xy²-x²y+2x²y²-9 from xy²+2x²y²-3x²y+3
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Answer:
(xy² + 2x²y² - 3x²y + 3) - (3xy² - x²y + 2x²y² - 9)
= xy² + 2x²y² - 3x²y + 3 - 3xy² + x²y - 2x²y² + 9
= xy² - 3xy² +2x²y² - 2 x²y² - 3x²y + x²y + 3 + 9
= - 2xy² + 0 - 2x²y + 12
= - 2xy² - 2x²y + 12
hope it helps you!!