sum of digit of a number 10^n -1 is 3798 then the value of n is
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sum of digit of a number 10^n -1 is 3798 then the value of n is
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Will be of the form 9999......... and therefore the sum of the digits will be 9 times the number of 9'ns. Thus, the number of nines is
Thus
Contains 422 nines. But since when subtracting 1 from 10^n, 1 gets carried over,
Brainliest!!!!