sum of the areas of two squares is 468 metre square the difference of their perimeters is 24m formulate the quadratic equation to find the sides of the two squares
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sum of the areas of two squares is 468 metre square the difference of their perimeters is 24m formulate the quadratic equation to find the sides of the two squares
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area of 2nd is b^2
a^2 + b^2 = 468
4(a-b) = 24
a-b =6
squaring both side
468-2ab=36
2ab=432
ab=216
a^2 + (216/a)^2=468