sum of the digits of a two digit no is 9 by interchanging the places of digits the number reduced by 63 find
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sum of the digits of a two digit no is 9 by interchanging the places of digits the number reduced by 63 find
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Let’s say x is the unit digit and y is the tenth digit.
y+x = 9 -> y=9-x
10x+y = 10y+x+63
10x+9-x = 10(9-x)+x+63
10x+9-x = 90–10x+x+63
18x = 18
x = 1
so y = 8
The number is 81