Sum of the digits of a two digit number is 5. If the difference between the number and the reversed number is 27. Find the number.
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Sum of the digits of a two digit number is 5. If the difference between the number and the reversed number is 27. Find the number.
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Answer:-
Let the digit at ten's place be x and digit at one's place be y.
→ The number = 10x + y
Given:
Sum of the digits = 5
⟶ x + y = 5
⟶ x = 5 - y -- equation (1).
Also,
Difference between original number & reversed number = 27
⟶ Original number - Reversed number = 27
⟶ 10x + y - (10y + x) = 27
Substitute the value of x from equation (1)
⟶ 10(5 - y) + y - 10y - (5 - y) = 27
⟶ 50 - 10y + y - 10y - 5 + y = 27
⟶ - 18y = 27 - 50 + 5
⟶ - 18y = - 18
⟶ y = - 18 / - 18
⟶ y = 1
Substitute the value of y in equation (1).
⟶ x = 5 - y
⟶ x = 5 - 1
⟶ x = 4
Hence,