Sum of three consecutive number of an AP is 15 and the sum of the square is 83 find the three terms
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Sum of three consecutive number of an AP is 15 and the sum of the square is 83 find the three terms
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ATQ ,
a-d+a+a+d = 15
3a = 15
a = 5 -----(1)
now , sum of the squares ,
(a-d)² +a² +(a+d)² = 83
a² + d² -2ad +a² +a² +d² +2ad = 83
3a² +2d² =83
3 ×25 + 2d² =83 ( from (1) )
75 +2d² = 83
2d² = 8
d² = 4
d = 2
so three consecutive term are
3 , 5 and 7