sum of two consecutive even numbers is 46. Find the smaller even number.
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sum of two consecutive even numbers is 46. Find the smaller even number.
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Answer:
let first number be x
Let the second number be x + 2
According to condition:
x + ( x+2) = 46
x +x +2=46
2x + 2 = 46
x = (46 - 2)/ 2
x = 22
So, the first number = x = 22
Second number = x+2 = 24
Hope this helps !
Step-by-step explanation:
Answer:
let two consecutive even numbers are x and x+2
[tex] \: \: \: \: \: \: \: according \: to \: question \\ x + x + 2 = 46 \\ 2x + 2 = 46 \\ 2x = 44 \\ = > x = 22[/tex]
then small even number is 22