Sum of two numbers is 78. If one exceeds
the other by 18 then numbers are
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Sum of two numbers is 78. If one exceeds
the other by 18 then numbers are
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Given,
Sum of two numbers is [tex]78[/tex]. If one exceeds the other by [tex]18[/tex].
One number be '[tex]x[/tex]'
According to the question,
One exceeds the other by [tex]18[/tex] be '[tex]x+18[/tex]'
Sum of two numbers is [tex]78[/tex]
[tex]x+x+18=78\\2x+18=78\\2x=78-18\\2x=60\\x=30[/tex]
Other number is [tex]x+18=30+18=48[/tex]
Therefore, the number is [tex]30[/tex] and [tex]48[/tex].
Answer:
[tex]30,48[/tex]
Step-by-step explanation:
Given data,
According to the given data,
[tex]x+x+18=78[/tex]
[tex]\Rightarrow 2x+18=78[/tex]
[tex]\Rightarrow 2x=60[/tex]
[tex]\Rightarrow x=30[/tex]
Therefore, the first number is [tex]30[/tex] and the second number is [tex]30+18=48[/tex]
Hence, the numbers are [tex]30,48[/tex].