A CAR ACCELERATES FROM REST AT 5M/S2 AND THEN RETARDS TO REST AT 3M/S2.THE MAXIMUM VELOCITY OF THE CAR IS 30M/S.WHAT IS THE DISTANCE COVERED BY THE CAR DURING ENTIRE JOURNEY
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A CAR ACCELERATES FROM REST AT 5M/S2 AND THEN RETARDS TO REST AT 3M/S2.THE MAXIMUM VELOCITY OF THE CAR IS 30M/S.WHAT IS THE DISTANCE COVERED BY THE CAR DURING ENTIRE JOURNEY
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Here, we will go for 2 cases.
Case 1 is case when car acclerated 5 m/s^2 from rest ( u = 0 ) and attained 30 m/s velocity ( v ). Let's keep values in equation.
Case 2 is case when car was moving with velocity of 30 m/s ( u ) but suddely applied breaks for retardation of 3 m/s^2 to come to rest ( v = 0 ). Let's keep values.
Total sistance covered = Case 1 + Case 2
= 90 m + 150 m
= 240 m
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