Without using trigonometric tables, Evaluate 2[cos 58⁰/sin 32⁰] - √3 [cos 38⁰ cosec 52⁰/tan 15⁰ tan 60⁰ tan 75⁰].Can anyone help me with this question?
Without using trigonometric tables, Evaluate 2[cos 58⁰/sin 32⁰] - √3 [cos 38⁰ cosec 52⁰/tan 15⁰ tan 60⁰ tan 75⁰].Can anyone help me with this question?
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Answer:
Step-by-step explanation:
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Step-by-step explanation:
2(cos58/sin32)-√3(cos38*cosec52/tan15*tan60*tan75)
= 2{cos58/sin(90-58)}-√3[{cos38*cosec(90-38)}/tan(90-75)*tan60*tan75]
= 2{cos58/cos58}-√3[cos38*sec38/cot75*tan60*tan75] (1/tanФ = cotФ)
= 2*1-√3[1/tan60]
= 2-√3(1/√3)
= 2-1
= 1