Tan80-tan10/tan70=how much
1) 0
2) 1
3) 2
4) 3
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Answer:
0
Step-by-step explanation:
if we sub tan80-tan10 its tan70
➸ Given:-
[tex]\Large{\bold{\frac{tan80°-tan10°}{tan70°}}}[/tex]
☣ To Find:-
☢ Solution:-
[tex]→\;\sf{\frac{tan80°-tan10°}{tan70°}}[/tex]
[tex]→\;\Large\sf{\frac{\frac{sin80°}{cos80°}-\frac{sin10°}{cos10°}}{\frac{sin70°}{cos70°}}}[/tex]
[tex]→\;\Large\sf{\frac{\frac{(sin80°cos10°-sin10°cos80°}{cos80°cos10°}}{\frac{sin70°}{cos70°}}}[/tex]
[tex]→\;\Large{\sf{\frac{sin(80°-10°).cos70°}{cos80°cos10°sin70°}}}[/tex]
[tex]→\;\Large{\sf{\frac{sin70°cos70°}{cos80°cos10°sin70°}}}[/tex]
[tex]→\;\Large{\sf{\frac{cos70°}{cos80°cos10°}}}[/tex]
[tex]→\;\Large{\sf{\frac{cos(80°-10°)}{cos80°cos10°}}}[/tex]
[tex]→\;\Large{\sf{\frac{\cancel{cos80°cos10°}+sin80°sin10°}{\cancel{cos80°cos10°}}}}[/tex]
[tex]→\;\sf{1+tan80°tan10°}[/tex]
[tex]→\;{\sf{1+tan(90°-10°) tan 10°}}[/tex]
[tex]→\;{\sf{1+cot10°tan10°}}[/tex]
[tex]→\;{\sf{1+1}}[/tex]
[tex]➝\;\bf{2}[/tex]
[tex]\boxed{\tt{@MrMonarque}}[/tex]
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