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square of larger no.= x^2
smaller no. =8
so the smaller no
is 8 times= 8x
so
ACC to the question
x^2-8x= 180
solve in equation
x^2-8x-180=0
x^2-18x+10x-180=0
x(x-18)+10x(x-18)=0
so the value of
x= -10, 18
negative no. can not be taken
so the smaller no.
√8x
√8×18
√144
=12
so the two positive no.
is 12,18