x^2
[tex]x2 - 4x + 1 is(2 + \sqrt{3} ) [/tex]
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x²-4x+1
Zeroes :
= -(-4) ±√(-4)²-4(1)(1) / 2(1)
= 4±√16-4 / 2
= 4±√12 / 2
= 2(2±√3) / 2
= 2±√3
Hope it helps u : )