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[tex]{\bold{Explanation\:Required}}[/tex]
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I hope that this image could be adequate to understand.
[tex]{\bold{Explanation\:Required}}[/tex]
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Answer:
AD=20cm
Step-by-step explanation:
let angle CAB=⊙
w.k.t. in triangle ABC
Cos ⊙=AB/BC
BC=CD+BD=41
cos⊙=AB/41 equation 1
now, in triangle ADB
angle D is right angled
so, cos ⊙=BD/AB
Cos ⊙=16/AB equation 2
in both equation 1 and 2 L.H.S are equal so R.H.S is also equal
i.e., AB/41=16/AB
AB^2=16×41
AB^2=656
Now in triangle ABD
By applying phthogoreas theorem
AB^2=AD^2+BD^2
656=AD^2+256
AD^2=400
AD=20cm