factorise the following using identities... 1)
[tex] {4y}^{2} - 4y + 1 \: dont \: send \: answer \: if \: u \: do \: not \: know[/tex]
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factorise the following using identities... 1)
[tex] {4y}^{2} - 4y + 1 \: dont \: send \: answer \: if \: u \: do \: not \: know[/tex]
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Here is ur answer !!!
4y²-4y +1
= (2y)²-2(2y)(1) + 1²
= (2y-1)²
= (2y-1)(2y-1)
Hope it helps u