If alpha, beta are zeroes of x^2 - 10x + 5, find the value of
[tex] \alpha { }^{ - 1} + \beta {}^{ - 1} .[/tex]
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If alpha, beta are zeroes of x^2 - 10x + 5, find the value of
[tex] \alpha { }^{ - 1} + \beta {}^{ - 1} .[/tex]
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Given f(x) = x^2 - 10x + 5.
Given α,β are the zeroes of x^2 - 10x + 5.
Here a = 1, b = -10, c = 5.
Now,
(i)
We know that Sum of zeroes = -b/a
= > α + β = -(-10)/1
= > α + β = 10.
(ii)
We know that Product of zeroes = c/a
= > αβ = (5/1)
= > αβ = 5.
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Now,
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