[tex]xy + zx + y ^{2} - z ^{2} [/tex]
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Answer:
[tex](y+z)(x+y-z)[/tex]
Step-by-step explanation:
Tip : If terms share same factor,
then we get (same factor) × (sum of the rest)
In other words [tex]ma+mb=m(a+b)[/tex].
Two terms xy and zx shares same factor, x.
The rest are y and z.
Therefore, [tex](xy+zx)=x(y+z)[/tex]
Now, we have [tex]y^2-z^2[/tex] and it is [tex](y+z)(y-z)[/tex] by identity.
Now, [tex]x(y+z)[/tex] and [tex](y+z)(y-z)[/tex] shares same factor, y+z.
The rest are [tex]x[/tex] and [tex]y-z[/tex].
Therefore, we get [tex](y+z)(x+y-z)[/tex].
Step-by-step explanation:
hope it's helpful
(y+z)(x+y−z)
Step-by-step explanation:
Tip : If terms share same factor,
then we get (same factor) × (sum of the rest)
In other words ma+mb=m(a+b)ma+mb=m(a+b) .
Two terms xy and zx shares same factor, x.
The rest are y and z.
Therefore, (xy+zx)=x(y+z)(xy+zx)=x(y+z)
Now, we have y^2-z^2y
2
−z
2
and it is (y+z)(y-z)(y+z)(y−z) by identity.
Now, x(y+z)x(y+z) and (y+z)(y-z)(y+z)(y−z) shares same factor, y+z.
hope it's helpful
The rest are xx and y-zy−z .
Therefore, we get (y+z)(x+y-z)(y+z)(x+y−z