Solve :
[tex](i^{10}+1)(i^9+1)(i^8+1)........(i+1)[/tex]
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Solve :
[tex](i^{10}+1)(i^9+1)(i^8+1)........(i+1)[/tex]
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Verified answer
We have to use this concept.
So,
Hence 0 is the answer.
Answer:
Step-by-step explanation:
Complex numbers:-
Given a series.
We know that iota follows a cyclic series.
i^4n=1
i^(4n+1)=i
i^(4n+2)=-1
i^(4n+3)=-i
where n€W
So, putting n=2,we get i^10=-1
We find that the first term i^10+1 becomes 0.
Anything multiplied by 0 becomes 0
So,answer is 0