[tex]integral \: of \: \frac{1}{x} \: is \: \: log(x) [/tex]
[tex]why \: integral \: of \: \frac{1}{x - 2} \: is \: equal \: to \: log \: | x - 2 | [/tex]
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[tex]integral \: of \: \frac{1}{x} \: is \: \: log(x) [/tex]
[tex]why \: integral \: of \: \frac{1}{x - 2} \: is \: equal \: to \: log \: | x - 2 | [/tex]
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Verified answer
Given:
To find:
Explanation:
Hence, the ∫1/x-2 = log|x-2|+C where C is some constant.