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[tex]\sf ✰QUESTION✰ [/tex]
[tex]1. \: \sin62° - \cos \: 28° \: \\ [/tex]
[tex] 2. \: cossec \: 35° - \sec \: 55°[/tex]
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[tex]\sf ✰QUESTION✰ [/tex]
[tex]1. \: \sin62° - \cos \: 28° \: \\ [/tex]
[tex] 2. \: cossec \: 35° - \sec \: 55°[/tex]
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Verified answer
Answer:
(1): 0
(2): 0
Step-by-step explanation:
A relation in sine and cosine is sin(90° - x) = cosx.
Similarly, cosec(90° - x) = secx.
(1): sin62° - cos28°
=> sin62° - sin(90° - 28°)
=> sin62° - sin62°
=> 0
(2) cosec35° - sec55°
=> cosec35° - cosec(90° - 55°)
=> cosec35° - cosec35°
=> 0
[tex]\Large\fbox{\sf\blue{Answer :}}[/tex]
[tex] \large \mathfrak{Q1.}[/tex] [tex] \sf{sin62° - cos28°}[/tex]
[tex] \to \sf{ sin62° - sin(90° - 28°) }[/tex]
[tex] \to \sf{ sin62° - sin62°}[/tex]
[tex] \implies \bf \red{0}[/tex]
[tex] \Large \mathfrak{Q2.}[/tex] [tex] \sf{cosec35° - sec55°}[/tex]
[tex] \to \sf{cosec35° - cosec(90° - 55°)}[/tex]
[tex] \to \sf{cosec35° - cosec35° }[/tex]
[tex] \implies \bf \red{0}[/tex]
[tex] \\ \\ [/tex]
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