prove that 3 - 2 root 2 equal to a + b root 2
prove that
[tex]3 - 2 \sqrt{2} = a + b \sqrt{2} [/tex]
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prove that 3 - 2 root 2 equal to a + b root 2
prove that
[tex]3 - 2 \sqrt{2} = a + b \sqrt{2} [/tex]
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Answer:
a = 3
b = - 2
Step-by-step explanation:
3 - 2√2 = a + b√2
When a = 3 and b = -2, 3 - 2√2 = a + b√2
∴ 3 - 2√2 = a + b√2
Answer:
please mark as branlist answer