Solve for general form
[tex] \sin(4x) = \cos(3x) [/tex]
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Answer:
Use the fact that cos(x)=sin(π2−x) to your advantage.
Setting this up, we get:
sin(4x)=sin(π2−3x)⟹4x=π2±3x+2πk
where k is an arbitrary integer. The ± comes from the fact that sin(x)=sin(π−x) which is the other angle that shares the same y value on the unit circle.