if,
[tex]\tt cosec\: \theta - sin\:\theta=a^3[/tex]
and,
[tex]\tt sec\: \theta - cos\: \theta =b^3[/tex]
then prove that,
[tex] \tt a^2b^2(a^2+b^2)=1[/tex]
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if,
[tex]\tt cosec\: \theta - sin\:\theta=a^3[/tex]
and,
[tex]\tt sec\: \theta - cos\: \theta =b^3[/tex]
then prove that,
[tex] \tt a^2b^2(a^2+b^2)=1[/tex]
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your answer hope it helps :-)
Step-by-step explanation:
refer to the attachment