find the value of a
[tex]2 {}^{a + 2} + 2 {}^{2} = 8 \\ [/tex]
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find the value of a
[tex]2 {}^{a + 2} + 2 {}^{2} = 8 \\ [/tex]
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Answer :-
To Solve :-
[tex] {2}^{a + 2} + {2}^{2} = 8[/tex]
Step By Step Solution :-
In the given question we have to find the value of a.
So let's do it !!
[tex]\implies\sf 2^{a+2}+2^2=8\\ \\\implies\sf 2^{a+2}=8-2^2\\ \\ \implies\sf2^{a+2}=8-4\\ \\ \implies\sf2^{a+2}=4\\ \\ \implies\sf2^{a+2}=2^2\\\\ \implies\sf Comparing \: powers\\ \\ \implies\sf \: a+2=2\\ \\ \implies\sf \: a=2-2\\ \\\implies\sf a=0[/tex]
Therefore a = 0
Check :-
L. H. S.
By substituting the value of a = 0
[tex] \implies \sf{2}^{0 + 2} + {2}^{2} \\ \\ \implies \sf {2}^{2} + {2}^{2} \\ \\ \implies \sf 4 + 4 = 8[/tex]
R. H. S.
=> 8
Therefore L. H. S. = R. H. S.
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