Find the value of following ÷
[tex] \frac{ \sqrt{32 + \sqrt{48} } }{ \sqrt{8 + \sqrt{12} } } [/tex]
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Find the value of following ÷
[tex] \frac{ \sqrt{32 + \sqrt{48} } }{ \sqrt{8 + \sqrt{12} } } [/tex]
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Answer:
2
Step-by-step explanation:
=(√32+√48)÷(√8+√12)
=(4√2+4√3)÷(2√2+2√3)
=4(√2+√3)÷2(√2+√3)
=4÷2
=2
Answer:
The value is two.
Step-by-step explanation:
In the last step take 4 common from numerator and 2 common from denominator.