[tex]\frak{\underline{Question}}:- \\ [/tex]
3) The pair of linear equations 3x - 5y - 4 = 0 and 2x + 7y - 12 = 0 have
[tex] \\ [/tex]
[tex]\\ \sf(a) \: \frac{1}{7} \\ \\ \sf(b) \: \frac{2}{7} \\ \\ \sf(c) \: \frac{3}{7} \\ \\ \sf(d) \: \frac{5}{7}[/tex]
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Step-by-step explanation:
I don't know what your question means
maybe if this is what you are looking for
hope it helps
Step-by-step explanation:
[tex]3x - 5y - 4 = 0 \\ = > 3x - 5y = 4 \: \: \: - (1) \\ = > 2x + 7y = 12 \: \: \: - (2) \\ [/tex]
multiplying (1) by 7 and (2) by 5 , we get ,
[tex]21x - 35y = 28 \\ = > 10x + 35y = 60 \\ = > 31x = 88 \\ = > x = \frac{88}{31} \\ = > x = 2 \frac{26}{31} [/tex]