Show that 1 +
[tex] {tan}^{2} {60}^{0} = {sec}^{2} {60}^{0} [/tex]
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Show that 1 +
[tex] {tan}^{2} {60}^{0} = {sec}^{2} {60}^{0} [/tex]
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Step-by-step explanation:
sec^2(theta)-tan^2(theta)=1
so
sec^2(60)=1+tan^2(60)
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