if a = 2, b= -2, c = 1
[tex] {a}^{2} b + {b}^{2}c + {c}^{2} a [/tex]
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if a = 2, b= -2, c = 1
[tex] {a}^{2} b + {b}^{2}c + {c}^{2} a [/tex]
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Answer:
Let's substitute the given values (a = 2), (b = -2), and (c = 1) into the expression (a²b + b²c + c²a):
[tex]\[ (2)^2(-2) + (-2)^2(1) + (1)^2(2) \][/tex]
Simplify each term:
[tex]\[ 4(-2) + 4 + 2 \][/tex]
Combine like terms:
[tex]\[ -8 + 4 + 2 \][/tex]
[tex]\[ -2 \][/tex]
So, when (a = 2), (b = -2), and (c = 1), the expression (a²b + b²c + c²a) evaluates to (-2) ..
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