Solve for x..
[tex] \bf \frac{5}{12}(m + 2) = \frac{2}{3}(2m + 1) + \frac{11}{6} [/tex]
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m = 20/-11
Given :
[tex]\bf \frac{5}{12}(m + 2) = \frac{2}{3}(2m + 1) + \frac{11}{6} \\ [/tex]
To do :
[tex]Solve \: for \: m[/tex]
Solution Explanation :
[tex]\bf \frac{5}{12}(m + 2) = \frac{2}{3}(2m + 1) + \frac{11}{6} \\ \\ \frac{5m + 10}{12} = \frac{4m + 2}{3} + \frac{11}{6} \\ \\ \frac{5m + 10}{12} = \frac{2(4m + 6) + 11}{6} \\ \\ \frac{5m + 10}{12} = \frac{8m + 12 + 11}{6} \\ \\ \frac{5m + 10}{12} = \frac{8m + 23}{6} \\ \\ 6(5m + 10) = 12(8m + 23) \\ \\ 30m + 60 = 96m + 276 \\ \\ 30m - 96m = 276 - 60 \\ \\ - 66m = 216 \\ \\ m = \frac{216}{ - 66} \\ \\ m = -3 .27[/tex]