Page : 1.8
Evalute : [tex][(x^{a+1})^{\frac {a^{2}}{a^{2}-1}}]^{1- \frac {1}{a}}[/tex]
a) 0
b) 1
c) xᵃ
d) x²
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Page : 1.8
Evalute : [tex][(x^{a+1})^{\frac {a^{2}}{a^{2}-1}}]^{1- \frac {1}{a}}[/tex]
a) 0
b) 1
c) xᵃ
d) x²
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here is your answer :-
look this attachment :-
hence , Option number C is correct .
☆ INDICES ☆
The answer is x^a
You just have to know the simple indices rules
(a^m)^n = a^mn
a^2 - b^2 = ( a + b )( a - b )
Your required steps are in above attachment refer it