50 Points :v:
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If a cubing equation [tex]x^3 - x^2 + 2x + 3[/tex]= 0
Has roots α, β, γ.
Then give the new equation for which the roots are as ;
1) α + β, β + γ, γ + α
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Answer:
equation : x^3-x^2+2x+3 = 0
zeroes : a,b and y ( a= alpha , b = beta , c = gamma )
= 1/1
zeroes of new polynomial : a+b , b+y , y+a
= 2( a+b+y )
from (1),
a+b+y = 1
2(a+b +y ) = 2 = -B/A
from (2),
===> 6 +a^2 + b^2 + y^2 = c/a
Answer:
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