Solve :-
[tex]\lim\limits_{x\to \frac{3}{2}} \left[\dfrac{\sin(2x-3)}{(2x-3)}\right][/tex]
I am unaware of any such method where x is not tending towards 0. Help me !!
Chapter-13 limits and derivatives
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Solve :-
[tex]\lim\limits_{x\to \frac{3}{2}} \left[\dfrac{\sin(2x-3)}{(2x-3)}\right][/tex]
I am unaware of any such method where x is not tending towards 0. Help me !!
Chapter-13 limits and derivatives
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Verified answer
If we put directly the value of x, we get
To solve this
we use method of Substitution
So, above expression can be reduced to
We know,
So, using this identity, we get
Hence,
Additional Information :-
Answer:
I will solve this math by La' Hospital's rule .
Rule :
La' Hospital's Rule tells us that if we have an indeterminate form 0/0 or ∞/∞ all we need to do is differentiate the numerator and differentiate the denominator and then take the limit.
Solution :