[tex]\huge{\bf{{\underline{\colorbox{black} {\color{white}{Question}}}}}}[/tex]
A pair of tangents are drawn from the origin to the circle x^2+y^2+20(x+y)+20=0 the equation of pair of tangents is?
Share
[tex]\huge{\bf{{\underline{\colorbox{black} {\color{white}{Question}}}}}}[/tex]
A pair of tangents are drawn from the origin to the circle x^2+y^2+20(x+y)+20=0 the equation of pair of tangents is?
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Verified answer
SOLUTION
Given equation of circle is :
S:x2+y2+20(x+y)+20=0
Comparing with general equation of circle, we get,
g=10,f=10,c=20
Equation of circle at (0,0) is :
S1:20
Equation of tangent to circle at (0,0) is :
T:10x+10y+20
Now, the equation of pair of tangents drawn from (0,0)to circle is :
SS1=T2
20(x2+y2+20(x+y)+20)=(10x+10y+2x²+2y² 5xy = 0
Step-by-step explanation:
pls make me brainlist pls dear plssssssss
Answer:
[tex]{\huge{\underline{\underline{\text{\color {plum}{❥Answer❥}}}}}} {\huge{\text{\color{plum}{:-}}}}[/tex]
Step-by-step explanation:
The equation of the circle can be rewritten in the standard form as follows:
(x+10)^2 + (y+10)^2 =100This represents a circle with center at (-10,-10) and radius10.
The equation of the pair of tangents from the origin to any circle with center at (h, k) and radius r is given by:
xx1 + yy1 = r^2where (x1, y1) are the coordinates of the center of the circle.
So, in this case, the equation of the pair of tangents from the origin to the given circle would be:
x(-10) + y(-10) =10^2This simplifies to:
-10x -10y =100Or, dividing through by -10:
x + y = -10So, the equation of the pair of tangents from the origin to the given circle is x + y = -10.