In the given figure, if
ar(∆ ALM)
ar(trapezium LMCB)=
[tex] \frac{9}{16} [/tex]
and LM||BC, Then AL:LB is equal to
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In the given figure, if
ar(∆ ALM)
ar(trapezium LMCB)=
[tex] \frac{9}{16} [/tex]
and LM||BC, Then AL:LB is equal to
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Answer:
answer: AL:LB = AM:MC (BY AA AXIOM)